# Default values when destructuring an array in JavaScript

Variables can have default values. In this case, if the array element is absent for the variable, the default value will be taken. In the following example, the variable `day` defaults to `1`:

`let arr = [2025, 12]; let [year, month, day = 1] = arr; console.log(year); // shows 2025 console.log(month); // shows 12 console.log(day); // shows 1`

But if there is a value in the array for the variable `day`, the default value will be ignored:

`let arr = [2025, 12, 31]; let [year, month, day = 1] = arr; console.log(year); // shows 2025 console.log(month); // shows 12 console.log(day); // shows 31`

In the following code, parts of the array are written to the corresponding variables:

`let arr = ['John', 'Smit', 'development', 'programmer']; let name = arr[0]; let surname = arr[1]; let department = arr[2]; let position; if (arr[3] !== undefined) { position = arr[3]; } else { position = 'trainee'; }`

Rework this code through destructuring according to the learned theory.

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