# Exceptions inside sets in regex in JavaScript

You already know that special characters inside `[]` become regular characters. There are, however, exceptions: if you need square brackets as regular characters inside `[ ]`, then you need to escape them with a backslash. For example, in the following code, the search pattern looks like this: there is a square bracket between x's:

`let str = 'x]x xax x[x x1x'; let res = str.replace(/x[\[\]]x/g, '!');`

As a result, the following will be written to the variable:

`'! xax ! x1x'`

Given a string:

`let str = 'x[]z x[[]]z x()z';`

Write a regex that matches all words in the pattern: letter `'x'`, then square brackets any number of times, then letter `'z'`.

Given a string:

`let str = 'x[]z x{}z x.z x()z x([])z';`

Write a regex that matches all words in the pattern: letter `'x'`, then any number of any brackets, then letter `'z'`.

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