# Extreme array values via spread in JavaScript

Look at the following code:

`let max = Math.max(1, 2, 3, 4, 5);`

As you can see, this code contains the maximum of the numbers. But what if our numbers are represented as an array? For example, like this:

`let arr = [1, 2, 3, 4, 5];`

Unfortunately, we cannot do the following:

`let arr = [1, 2, 3, 4, 5]; let max = Math.max(arr); // you can't pass an array here`

Of course, we can manually put the array elements into `Math.max`, like this:

`let arr = [1, 2, 3, 4, 5]; let max = Math.max(arr[0], arr[1], arr[2], arr[3], arr[4]);`

However, in this case, any universality is lost: our code will only find the maximum value for an array of `5` elements.

What if we need more or less elements in the array? There is a solution! We use the spread operator:

`let arr = [1, 2, 3, 4, 5] let max = Math.max(...arr);`

This code, despite its simplicity, is very powerful. After all, `Math.max` can take any number of parameters, which means that using the spread operator, we can use an array of arbitrary size!

Given an array of numbers. Using `Math.min` and spread, display the minimum value of the array.

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