# Checking parts of hour with if-else in JavaScript

Suppose we have the variable `min` that stores the number of minutes from `1` to `60`:

`let min = 10;`

Let's determine in which quarter of an hour the specified number of minutes falls:

`let min = 10; if (min >= 0 && min <= 14) { console.log('1st quarter'); } if (min >= 15 && min <= 29) { console.log('2nd quarter'); } if (min >= 30 && min <= 44) { console.log('3rd quarter'); } if (min >= 45 && min <= 59) { console.log('4th quarter'); }`

Solve a similar problem, only determine what third of the hour the specified number of minutes falls in.

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